Base | Representation |
---|---|
bin | 1100110110000010000100… |
… | …1010100010110000001111 |
3 | 1212000002101221211101222222 |
4 | 3031200201022202300033 |
5 | 3322340143133144132 |
6 | 50011424534125555 |
7 | 2655211312566116 |
oct | 315404112426017 |
9 | 55002357741888 |
10 | 14122408881167 |
11 | 4555309708894 |
12 | 17010261b08bb |
13 | 7b5978216492 |
14 | 36b7576a6c7d |
15 | 1975525d1412 |
hex | cd8212a2c0f |
14122408881167 has 2 divisors, whose sum is σ = 14122408881168. Its totient is φ = 14122408881166.
The previous prime is 14122408881157. The next prime is 14122408881193. The reversal of 14122408881167 is 76118880422141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14122408881167 - 240 = 13022897253391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14122408881157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061204440583 + 7061204440584.
It is an arithmetic number, because the mean of its divisors is an integer number (7061204440584).
Almost surely, 214122408881167 is an apocalyptic number.
14122408881167 is a deficient number, since it is larger than the sum of its proper divisors (1).
14122408881167 is an equidigital number, since it uses as much as digits as its factorization.
14122408881167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1376256, while the sum is 53.
The spelling of 14122408881167 in words is "fourteen trillion, one hundred twenty-two billion, four hundred eight million, eight hundred eighty-one thousand, one hundred sixty-seven".
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