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14123034581 is a prime number
BaseRepresentation
bin11010010011100110…
…00110011111010101
31100110020222111021212
431021303012133111
5212410444101311
610253225351205
71006660545635
oct151163063725
940406874255
1014123034581
115a980a2a07
1228a1938505
131440c590c6
1497d9826c5
15579d37c8b
hex349cc67d5

14123034581 has 2 divisors, whose sum is σ = 14123034582. Its totient is φ = 14123034580.

The previous prime is 14123034557. The next prime is 14123034589. The reversal of 14123034581 is 18543032141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10661595025 + 3461439556 = 103255^2 + 58834^2 .

It is an emirp because it is prime and its reverse (18543032141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14123034581 - 210 = 14123033557 is a prime.

It is a super-2 number, since 2×141230345812 (a number of 21 digits) contains 22 as substring.

It is an alternating number because its digits alternate between odd and even.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14123034589) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061517290 + 7061517291.

It is an arithmetic number, because the mean of its divisors is an integer number (7061517291).

Almost surely, 214123034581 is an apocalyptic number.

It is an amenable number.

14123034581 is a deficient number, since it is larger than the sum of its proper divisors (1).

14123034581 is an equidigital number, since it uses as much as digits as its factorization.

14123034581 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 32.

The spelling of 14123034581 in words is "fourteen billion, one hundred twenty-three million, thirty-four thousand, five hundred eighty-one".