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141231020111 is a prime number
BaseRepresentation
bin1000001110001000000…
…1100101100001001111
3111111112122002011212122
42003202001211201033
54303220120120421
6144514114523155
713126556602136
oct2034201454117
9444478064778
10141231020111
1154994257835
1223455b964bb
131041992786c
146b9ad1491d
153a18d382ab
hex20e206584f

141231020111 has 2 divisors, whose sum is σ = 141231020112. Its totient is φ = 141231020110.

The previous prime is 141231020101. The next prime is 141231020113. The reversal of 141231020111 is 111020132141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141231020111 - 226 = 141163911247 is a prime.

Together with 141231020113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 141231020111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141231020113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70615510055 + 70615510056.

It is an arithmetic number, because the mean of its divisors is an integer number (70615510056).

Almost surely, 2141231020111 is an apocalyptic number.

141231020111 is a deficient number, since it is larger than the sum of its proper divisors (1).

141231020111 is an equidigital number, since it uses as much as digits as its factorization.

141231020111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 141231020111 its reverse (111020132141), we get a palindrome (252251152252).

The spelling of 141231020111 in words is "one hundred forty-one billion, two hundred thirty-one million, twenty thousand, one hundred eleven".