Base | Representation |
---|---|
bin | 10100100011010101011… |
… | …111100110000001101001 |
3 | 12000000110210010200210221 |
4 | 110203111133212001221 |
5 | 141114423230233223 |
6 | 3000452125010041 |
7 | 204015611202445 |
oct | 24432537460151 |
9 | 5000423120727 |
10 | 1412331102313 |
11 | 4a4a6a0a6a3a |
12 | 1a98769b3921 |
13 | a324a539111 |
14 | 4c5001b5825 |
15 | 26b109d4b5d |
hex | 148d57e6069 |
1412331102313 has 2 divisors, whose sum is σ = 1412331102314. Its totient is φ = 1412331102312.
The previous prime is 1412331102311. The next prime is 1412331102319. The reversal of 1412331102313 is 3132011332141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1125406965904 + 286924136409 = 1060852^2 + 535653^2 .
It is a cyclic number.
It is not a de Polignac number, because 1412331102313 - 21 = 1412331102311 is a prime.
Together with 1412331102311, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1412331102311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706165551156 + 706165551157.
It is an arithmetic number, because the mean of its divisors is an integer number (706165551157).
Almost surely, 21412331102313 is an apocalyptic number.
It is an amenable number.
1412331102313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412331102313 is an equidigital number, since it uses as much as digits as its factorization.
1412331102313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1412331102313 its reverse (3132011332141), we get a palindrome (4544342434454).
The spelling of 1412331102313 in words is "one trillion, four hundred twelve billion, three hundred thirty-one million, one hundred two thousand, three hundred thirteen".
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