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14123443253 is a prime number
BaseRepresentation
bin11010010011101001…
…01010010000110101
31100110021202020212212
431021310222100311
5212411100141003
610253242223205
71006664200253
oct151164522065
940407666785
1014123443253
115a98351a57
1228a1ab4b05
13144107011a
1497da4b5d3
15579db8dd8
hex349d2a435

14123443253 has 2 divisors, whose sum is σ = 14123443254. Its totient is φ = 14123443252.

The previous prime is 14123443249. The next prime is 14123443289. The reversal of 14123443253 is 35234432141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11299264804 + 2824178449 = 106298^2 + 53143^2 .

It is an emirp because it is prime and its reverse (35234432141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14123443253 - 22 = 14123443249 is a prime.

It is a super-2 number, since 2×141234432532 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14123442253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061721626 + 7061721627.

It is an arithmetic number, because the mean of its divisors is an integer number (7061721627).

Almost surely, 214123443253 is an apocalyptic number.

It is an amenable number.

14123443253 is a deficient number, since it is larger than the sum of its proper divisors (1).

14123443253 is an equidigital number, since it uses as much as digits as its factorization.

14123443253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 34560, while the sum is 32.

Adding to 14123443253 its reverse (35234432141), we get a palindrome (49357875394).

The spelling of 14123443253 in words is "fourteen billion, one hundred twenty-three million, four hundred forty-three thousand, two hundred fifty-three".