Base | Representation |
---|---|
bin | 10100100011011010011… |
… | …000100010110111001111 |
3 | 12000000200111111122221202 |
4 | 110203122120202313033 |
5 | 141120110230443211 |
6 | 3000504215220115 |
7 | 204020625414566 |
oct | 24433230426717 |
9 | 5000614448852 |
10 | 1412413140431 |
11 | 4a500143a437 |
12 | 1a989a37763b |
13 | a3261531097 |
14 | 4c50b04cbdd |
15 | 26b17cdc53b |
hex | 148da622dcf |
1412413140431 has 2 divisors, whose sum is σ = 1412413140432. Its totient is φ = 1412413140430.
The previous prime is 1412413140361. The next prime is 1412413140449. The reversal of 1412413140431 is 1340413142141.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1412413140431 is a prime.
It is a super-2 number, since 2×14124131404312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1412413140394 and 1412413140403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1412413140451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706206570215 + 706206570216.
It is an arithmetic number, because the mean of its divisors is an integer number (706206570216).
Almost surely, 21412413140431 is an apocalyptic number.
1412413140431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412413140431 is an equidigital number, since it uses as much as digits as its factorization.
1412413140431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4608, while the sum is 29.
Adding to 1412413140431 its reverse (1340413142141), we get a palindrome (2752826282572).
The spelling of 1412413140431 in words is "one trillion, four hundred twelve billion, four hundred thirteen million, one hundred forty thousand, four hundred thirty-one".
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