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1412661100559 is a prime number
BaseRepresentation
bin10100100011101001001…
…010011100000000001111
312000001022210002100022012
4110203221022130000033
5141121112220204214
63000544554011435
7204030026142452
oct24435112340017
95001283070265
101412661100559
114a51193aa565
121a9949416b7b
13a32a0a0b157
144c531d57499
1526b2e96c03e
hex148e929c00f

1412661100559 has 2 divisors, whose sum is σ = 1412661100560. Its totient is φ = 1412661100558.

The previous prime is 1412661100531. The next prime is 1412661100561. The reversal of 1412661100559 is 9550011662141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1412661100559 - 212 = 1412661096463 is a prime.

It is a super-2 number, since 2×14126611005592 (a number of 25 digits) contains 22 as substring.

Together with 1412661100561, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1412661100259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706330550279 + 706330550280.

It is an arithmetic number, because the mean of its divisors is an integer number (706330550280).

Almost surely, 21412661100559 is an apocalyptic number.

1412661100559 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412661100559 is an equidigital number, since it uses as much as digits as its factorization.

1412661100559 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 41.

The spelling of 1412661100559 in words is "one trillion, four hundred twelve billion, six hundred sixty-one million, one hundred thousand, five hundred fifty-nine".