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14127212903 is a prime number
BaseRepresentation
bin11010010100000110…
…00010100101100111
31100110112211202212112
431022003002211213
5212413031303103
610253455111235
71010041220426
oct151203024547
940415752775
1014127212903
115a9a497171
1228a321251b
131441a8cb9b
1498034d2bd
1557a3b0cd8
hex34a0c2967

14127212903 has 2 divisors, whose sum is σ = 14127212904. Its totient is φ = 14127212902.

The previous prime is 14127212791. The next prime is 14127212909. The reversal of 14127212903 is 30921272141.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14127212903 is a prime.

It is an alternating number because its digits alternate between odd and even.

It is a self number, because there is not a number n which added to its sum of digits gives 14127212903.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14127212909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7063606451 + 7063606452.

It is an arithmetic number, because the mean of its divisors is an integer number (7063606452).

Almost surely, 214127212903 is an apocalyptic number.

14127212903 is a deficient number, since it is larger than the sum of its proper divisors (1).

14127212903 is an equidigital number, since it uses as much as digits as its factorization.

14127212903 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 32.

The spelling of 14127212903 in words is "fourteen billion, one hundred twenty-seven million, two hundred twelve thousand, nine hundred three".