Base | Representation |
---|---|
bin | 100000000111110011110001… |
… | …110001110111110010100111 |
3 | 200112012200012101002110101122 |
4 | 200013303301301313302213 |
5 | 122004113344343321123 |
6 | 1220244233551044155 |
7 | 41520501260301623 |
oct | 4007636161676247 |
9 | 615180171073348 |
10 | 141274120682663 |
11 | 41018022131271 |
12 | 13a17a5521065b |
13 | 60aa128069cc7 |
14 | 26c59bd7d8183 |
15 | 114ece644abc8 |
hex | 807cf1c77ca7 |
141274120682663 has 2 divisors, whose sum is σ = 141274120682664. Its totient is φ = 141274120682662.
The previous prime is 141274120682647. The next prime is 141274120682729. The reversal of 141274120682663 is 366286021472141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141274120682663 - 24 = 141274120682647 is a prime.
It is a super-3 number, since 3×1412741206826633 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141274120682063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70637060341331 + 70637060341332.
It is an arithmetic number, because the mean of its divisors is an integer number (70637060341332).
Almost surely, 2141274120682663 is an apocalyptic number.
141274120682663 is a deficient number, since it is larger than the sum of its proper divisors (1).
141274120682663 is an equidigital number, since it uses as much as digits as its factorization.
141274120682663 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4644864, while the sum is 53.
The spelling of 141274120682663 in words is "one hundred forty-one trillion, two hundred seventy-four billion, one hundred twenty million, six hundred eighty-two thousand, six hundred sixty-three".
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