Base | Representation |
---|---|
bin | 1100110110011110011001… |
… | …0111011100010100010111 |
3 | 1212000211000212002012202221 |
4 | 3031213212113130110113 |
5 | 3323001231124412102 |
6 | 50015123230443211 |
7 | 2655600610126045 |
oct | 315474627342427 |
9 | 55024025065687 |
10 | 14130012341527 |
11 | 4558560664125 |
12 | 17025a8663507 |
13 | 7b65ba55a054 |
14 | 36bc7942b395 |
15 | 197849d9d637 |
hex | cd9e65dc517 |
14130012341527 has 2 divisors, whose sum is σ = 14130012341528. Its totient is φ = 14130012341526.
The previous prime is 14130012341509. The next prime is 14130012341569. The reversal of 14130012341527 is 72514321003141.
It is a weak prime.
It is an emirp because it is prime and its reverse (72514321003141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14130012341527 - 219 = 14130011817239 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14130012341492 and 14130012341501.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14130012348527) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065006170763 + 7065006170764.
It is an arithmetic number, because the mean of its divisors is an integer number (7065006170764).
Almost surely, 214130012341527 is an apocalyptic number.
14130012341527 is a deficient number, since it is larger than the sum of its proper divisors (1).
14130012341527 is an equidigital number, since it uses as much as digits as its factorization.
14130012341527 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 34.
Adding to 14130012341527 its reverse (72514321003141), we get a palindrome (86644333344668).
The spelling of 14130012341527 in words is "fourteen trillion, one hundred thirty billion, twelve million, three hundred forty-one thousand, five hundred twenty-seven".
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