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141300212423969 is a prime number
BaseRepresentation
bin100000001000001100000100…
…111101111101110100100001
3200112022011112202022020201202
4200020030010331331310201
5122010030313340031334
61220304231011410545
741522413662401354
oct4010140475756441
9615264482266652
10141300212423969
11410280a1251735
1213a20b172b3a55
1360ac7258220a1
1426c6d76b7029b
151150821dc217e
hex808304f7dd21

141300212423969 has 2 divisors, whose sum is σ = 141300212423970. Its totient is φ = 141300212423968.

The previous prime is 141300212423879. The next prime is 141300212424047. The reversal of 141300212423969 is 969324212003141.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 128084900851600 + 13215311572369 = 11317460^2 + 3635287^2 .

It is a cyclic number.

It is not a de Polignac number, because 141300212423969 - 216 = 141300212358433 is a prime.

It is a super-2 number, since 2×1413002124239692 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (141300212423269) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70650106211984 + 70650106211985.

It is an arithmetic number, because the mean of its divisors is an integer number (70650106211985).

Almost surely, 2141300212423969 is an apocalyptic number.

It is an amenable number.

141300212423969 is a deficient number, since it is larger than the sum of its proper divisors (1).

141300212423969 is an equidigital number, since it uses as much as digits as its factorization.

141300212423969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 559872, while the sum is 47.

The spelling of 141300212423969 in words is "one hundred forty-one trillion, three hundred billion, two hundred twelve million, four hundred twenty-three thousand, nine hundred sixty-nine".