1413002223221 has 2 divisors, whose sum is σ = 1413002223222. Its totient is φ = 1413002223220.

The previous prime is 1413002223169. The next prime is 1413002223223. The reversal of 1413002223221 is 1223222003141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1068920260996 + 344081962225 = 1033886^2 + 586585^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1413002223221 is a prime.

It is a super-2 number, since 2×1413002223221² (a number of 25 digits) contains 22 as substring.

Together with 1413002223223, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1413002223223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706501111610 + 706501111611.

It is an arithmetic number, because the mean of its divisors is an integer number (706501111611).

Almost surely, 2^{1413002223221} is an apocalyptic number.

It is an amenable number.

1413002223221 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413002223221 is an equidigital number, since it uses as much as digits as its factorization.

1413002223221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1413002223221 its reverse (1223222003141), we get a palindrome (2636224226362).

The spelling of 1413002223221 in words is "one trillion, four hundred thirteen billion, two million, two hundred twenty-three thousand, two hundred twenty-one".