14130553551132 has 24 divisors (see below), whose sum is σ = 33672808463616. Its totient is φ = 4609967825008.

The previous prime is 14130553551119. The next prime is 14130553551137. The reversal of 14130553551132 is 23115535503141.

It is a super-3 number, since 3×14130553551132³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14130553551137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12527085918 + ... + 12527087045.

It is an arithmetic number, because the mean of its divisors is an integer number (1403033685984).

Almost surely, 2^{14130553551132} is an apocalyptic number.

14130553551132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

14130553551132 is an abundant number, since it is smaller than the sum of its proper divisors (19542254912484).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14130553551132 is a wasteful number, since it uses less digits than its factorization.

14130553551132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25054173017 (or 25054173015 counting only the distinct ones).

The product of its (nonzero) digits is 135000, while the sum is 39.

The spelling of 14130553551132 in words is "fourteen trillion, one hundred thirty billion, five hundred fifty-three million, five hundred fifty-one thousand, one hundred thirty-two".