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1413111612431 is a prime number
BaseRepresentation
bin10100100100000100000…
…001000000010000001111
312000002111011210201102002
4110210010001000100033
5141123023033044211
63001101410022515
7204044136343241
oct24440401002017
95002434721362
101413111612431
114a532a735822
121a9a54277a3b
13a3343156b1c
144c575b0a091
1526b592ac03b
hex1490404040f

1413111612431 has 2 divisors, whose sum is σ = 1413111612432. Its totient is φ = 1413111612430.

The previous prime is 1413111612401. The next prime is 1413111612457. The reversal of 1413111612431 is 1342161113141.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1413111612431 - 238 = 1138233705487 is a prime.

It is a super-2 number, since 2×14131116124312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1413111612394 and 1413111612403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1413111612401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706555806215 + 706555806216.

It is an arithmetic number, because the mean of its divisors is an integer number (706555806216).

Almost surely, 21413111612431 is an apocalyptic number.

1413111612431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413111612431 is an equidigital number, since it uses as much as digits as its factorization.

1413111612431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1728, while the sum is 29.

Adding to 1413111612431 its reverse (1342161113141), we get a palindrome (2755272725572).

The spelling of 1413111612431 in words is "one trillion, four hundred thirteen billion, one hundred eleven million, six hundred twelve thousand, four hundred thirty-one".