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141312000000 = 21735623
BaseRepresentation
bin1000001110011011011…
…0100000000000000000
3111111202021110101101210
42003212312200000000
54303401333000000
6144530130330120
713131562116123
oct2034666400000
9444667411353
10141312000000
1154a25a38166
1223479129940
131043063bc62
146ba79943ba
153a20ed2350
hex20e6da0000

141312000000 has 504 divisors, whose sum is σ = 491511833568. Its totient is φ = 36044800000.

The previous prime is 141311999999. The next prime is 141312000001. The reversal of 141312000000 is 213141.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (141311999999) and next prime (141312000001).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 141312000000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141312000001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 6143999989 + ... + 6144000011.

It is an arithmetic number, because the mean of its divisors is an integer number (975221892).

Almost surely, 2141312000000 is an apocalyptic number.

141312000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 141312000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (245755916784).

141312000000 is an abundant number, since it is smaller than the sum of its proper divisors (350199833568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141312000000 is an frugal number, since it uses more digits than its factorization.

141312000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90 (or 33 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 141312000000 its reverse (213141), we get a palindrome (141312213141).

The spelling of 141312000000 in words is "one hundred forty-one billion, three hundred twelve million", and thus it is an aban number.