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141312213179 is a prime number
BaseRepresentation
bin1000001110011011011…
…1010100000010111011
3111111202021212012211022
42003212313110002323
54303401411310204
6144530135053055
713131563664464
oct2034667240273
9444667765738
10141312213179
1154a26073345
122347921118b
13104306b4cb7
146ba7a0bd6b
153a210255be
hex20e6dd40bb

141312213179 has 2 divisors, whose sum is σ = 141312213180. Its totient is φ = 141312213178.

The previous prime is 141312213149. The next prime is 141312213181. The reversal of 141312213179 is 971312213141.

141312213179 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (971312213141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141312213179 - 228 = 141043777723 is a prime.

Together with 141312213181, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (141312213109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70656106589 + 70656106590.

It is an arithmetic number, because the mean of its divisors is an integer number (70656106590).

Almost surely, 2141312213179 is an apocalyptic number.

141312213179 is a deficient number, since it is larger than the sum of its proper divisors (1).

141312213179 is an equidigital number, since it uses as much as digits as its factorization.

141312213179 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 9072, while the sum is 35.

The spelling of 141312213179 in words is "one hundred forty-one billion, three hundred twelve million, two hundred thirteen thousand, one hundred seventy-nine".