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141312213149 is a prime number
BaseRepresentation
bin1000001110011011011…
…1010100000010011101
3111111202021212012210012
42003212313110002131
54303401411310044
6144530135053005
713131563664422
oct2034667240235
9444667765705
10141312213149
1154a26073318
1223479211165
13104306b4c93
146ba7a0bd49
153a2102559e
hex20e6dd409d

141312213149 has 2 divisors, whose sum is σ = 141312213150. Its totient is φ = 141312213148.

The previous prime is 141312213127. The next prime is 141312213179. The reversal of 141312213149 is 941312213141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 136009752025 + 5302461124 = 368795^2 + 72818^2 .

It is an emirp because it is prime and its reverse (941312213141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141312213149 - 28 = 141312212893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141312213109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70656106574 + 70656106575.

It is an arithmetic number, because the mean of its divisors is an integer number (70656106575).

Almost surely, 2141312213149 is an apocalyptic number.

It is an amenable number.

141312213149 is a deficient number, since it is larger than the sum of its proper divisors (1).

141312213149 is an equidigital number, since it uses as much as digits as its factorization.

141312213149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5184, while the sum is 32.

The spelling of 141312213149 in words is "one hundred forty-one billion, three hundred twelve million, two hundred thirteen thousand, one hundred forty-nine".