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14131311449 is a prime number
BaseRepresentation
bin11010010100100101…
…01011001101011001
31100110211120000000112
431022102223031121
5212420103431244
610254123014105
71010121110513
oct151222531531
940424500015
1014131311449
115aa18364a2
1228a466a335
131442896568
14980ad8bb3
1557a92039e
hex34a4ab359

14131311449 has 2 divisors, whose sum is σ = 14131311450. Its totient is φ = 14131311448.

The previous prime is 14131311379. The next prime is 14131311451. The reversal of 14131311449 is 94411313141.

14131311449 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13768675600 + 362635849 = 117340^2 + 19043^2 .

It is a cyclic number.

It is not a de Polignac number, because 14131311449 - 28 = 14131311193 is a prime.

Together with 14131311451, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14131311479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065655724 + 7065655725.

It is an arithmetic number, because the mean of its divisors is an integer number (7065655725).

Almost surely, 214131311449 is an apocalyptic number.

It is an amenable number.

14131311449 is a deficient number, since it is larger than the sum of its proper divisors (1).

14131311449 is an equidigital number, since it uses as much as digits as its factorization.

14131311449 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 32.

The spelling of 14131311449 in words is "fourteen billion, one hundred thirty-one million, three hundred eleven thousand, four hundred forty-nine".