Base | Representation |
---|---|
bin | 10100100100001000100… |
… | …010001101100101100111 |
3 | 12000002200110110110222121 |
4 | 110210020202031211213 |
5 | 141123201440123123 |
6 | 3001113115010411 |
7 | 204046046634055 |
oct | 24441042154547 |
9 | 5002613413877 |
10 | 1413187426663 |
11 | 4a5369508111 |
12 | 1a9a75739a07 |
13 | a3355a7cc0c |
14 | 4c581c031d5 |
15 | 26b60c8575d |
hex | 1490888d967 |
1413187426663 has 2 divisors, whose sum is σ = 1413187426664. Its totient is φ = 1413187426662.
The previous prime is 1413187426661. The next prime is 1413187426691. The reversal of 1413187426663 is 3666247813141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1413187426663 - 21 = 1413187426661 is a prime.
Together with 1413187426661, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1413187426663.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1413187426661) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706593713331 + 706593713332.
It is an arithmetic number, because the mean of its divisors is an integer number (706593713332).
Almost surely, 21413187426663 is an apocalyptic number.
1413187426663 is a deficient number, since it is larger than the sum of its proper divisors (1).
1413187426663 is an equidigital number, since it uses as much as digits as its factorization.
1413187426663 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3483648, while the sum is 52.
The spelling of 1413187426663 in words is "one trillion, four hundred thirteen billion, one hundred eighty-seven million, four hundred twenty-six thousand, six hundred sixty-three".
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