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1413187426663 is a prime number
BaseRepresentation
bin10100100100001000100…
…010001101100101100111
312000002200110110110222121
4110210020202031211213
5141123201440123123
63001113115010411
7204046046634055
oct24441042154547
95002613413877
101413187426663
114a5369508111
121a9a75739a07
13a3355a7cc0c
144c581c031d5
1526b60c8575d
hex1490888d967

1413187426663 has 2 divisors, whose sum is σ = 1413187426664. Its totient is φ = 1413187426662.

The previous prime is 1413187426661. The next prime is 1413187426691. The reversal of 1413187426663 is 3666247813141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1413187426663 - 21 = 1413187426661 is a prime.

Together with 1413187426661, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1413187426663.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1413187426661) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706593713331 + 706593713332.

It is an arithmetic number, because the mean of its divisors is an integer number (706593713332).

Almost surely, 21413187426663 is an apocalyptic number.

1413187426663 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413187426663 is an equidigital number, since it uses as much as digits as its factorization.

1413187426663 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3483648, while the sum is 52.

The spelling of 1413187426663 in words is "one trillion, four hundred thirteen billion, one hundred eighty-seven million, four hundred twenty-six thousand, six hundred sixty-three".