1413301130009 has 2 divisors, whose sum is σ = 1413301130010. Its totient is φ = 1413301130008.

The previous prime is 1413301129997. The next prime is 1413301130011. The reversal of 1413301130009 is 9000311033141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1262735401225 + 150565728784 = 1123715^2 + 388028^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413301130009 - 2¹⁶ = 1413301064473 is a prime.

Together with 1413301130011, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1413301130009.

It is not a weakly prime, because it can be changed into another prime (1413301130099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706650565004 + 706650565005.

It is an arithmetic number, because the mean of its divisors is an integer number (706650565005).

Almost surely, 2^{1413301130009} is an apocalyptic number.

It is an amenable number.

1413301130009 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413301130009 is an equidigital number, since it uses as much as digits as its factorization.

1413301130009 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 26.

The spelling of 1413301130009 in words is "one trillion, four hundred thirteen billion, three hundred one million, one hundred thirty thousand, nine".