Base | Representation |
---|---|
bin | 100000001000101010101001… |
… | …000011000101110101100111 |
3 | 200112102022020212100221120121 |
4 | 200020222221003011311213 |
5 | 122011100021140031043 |
6 | 1220331255254142411 |
7 | 41524655144246446 |
oct | 4010525103056547 |
9 | 615368225327517 |
10 | 141333030002023 |
11 | 41040001989872 |
12 | 13a27355951a07 |
13 | 60b285585a322 |
14 | 26c87ab496d5d |
15 | 11515e3058ded |
hex | 808aa90c5d67 |
141333030002023 has 2 divisors, whose sum is σ = 141333030002024. Its totient is φ = 141333030002022.
The previous prime is 141333030001991. The next prime is 141333030002041. The reversal of 141333030002023 is 320200030333141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141333030002023 - 25 = 141333030001991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141333030002053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70666515001011 + 70666515001012.
It is an arithmetic number, because the mean of its divisors is an integer number (70666515001012).
Almost surely, 2141333030002023 is an apocalyptic number.
141333030002023 is a deficient number, since it is larger than the sum of its proper divisors (1).
141333030002023 is an equidigital number, since it uses as much as digits as its factorization.
141333030002023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 141333030002023 its reverse (320200030333141), we get a palindrome (461533060335164).
The spelling of 141333030002023 in words is "one hundred forty-one trillion, three hundred thirty-three billion, thirty million, two thousand, twenty-three".
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