1413341043251 has 2 divisors, whose sum is σ = 1413341043252. Its totient is φ = 1413341043250.

The previous prime is 1413341043211. The next prime is 1413341043253. The reversal of 1413341043251 is 1523401433141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1413341043251 - 2¹⁰ = 1413341042227 is a prime.

Together with 1413341043253, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1413341043253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706670521625 + 706670521626.

It is an arithmetic number, because the mean of its divisors is an integer number (706670521626).

Almost surely, 2^{1413341043251} is an apocalyptic number.

1413341043251 is a deficient number, since it is larger than the sum of its proper divisors (1).

1413341043251 is an equidigital number, since it uses as much as digits as its factorization.

1413341043251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 1413341043251 its reverse (1523401433141), we get a palindrome (2936742476392).

The spelling of 1413341043251 in words is "one trillion, four hundred thirteen billion, three hundred forty-one million, forty-three thousand, two hundred fifty-one".