141343331220142 has 4 divisors (see below), whose sum is σ = 212014996830216. Its totient is φ = 70671665610070.

The previous prime is 141343331220121. The next prime is 141343331220211. The reversal of 141343331220142 is 241022133343141.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 141343331220098 and 141343331220107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35335832805034 + ... + 35335832805037.

It is an arithmetic number, because the mean of its divisors is an integer number (53003749207554).

Almost surely, 2^{141343331220142} is an apocalyptic number.

141343331220142 is a deficient number, since it is larger than the sum of its proper divisors (70671665610074).

141343331220142 is an equidigital number, since it uses as much as digits as its factorization.

141343331220142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70671665610073.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 141343331220142 its reverse (241022133343141), we get a palindrome (382365464563283).

The spelling of 141343331220142 in words is "one hundred forty-one trillion, three hundred forty-three billion, three hundred thirty-one million, two hundred twenty thousand, one hundred forty-two".