1414051440311 has 2 divisors, whose sum is σ = 1414051440312. Its totient is φ = 1414051440310.

The previous prime is 1414051440293. The next prime is 1414051440349. The reversal of 1414051440311 is 1130441504141.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (1130441504141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1414051440311 - 2²⁶ = 1413984331447 is a prime.

It is a super-2 number, since 2×1414051440311² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1414051440511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707025720155 + 707025720156.

It is an arithmetic number, because the mean of its divisors is an integer number (707025720156).

Almost surely, 2^{1414051440311} is an apocalyptic number.

1414051440311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414051440311 is an equidigital number, since it uses as much as digits as its factorization.

1414051440311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 1414051440311 its reverse (1130441504141), we get a palindrome (2544492944452).

The spelling of 1414051440311 in words is "one trillion, four hundred fourteen billion, fifty-one million, four hundred forty thousand, three hundred eleven".