141408131 has 2 divisors, whose sum is σ = 141408132. Its totient is φ = 141408130.

The previous prime is 141408121. The next prime is 141408133. The reversal of 141408131 is 131804141.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141408131 - 2¹⁰ = 141407107 is a prime.

It is a super-2 number, since 2×141408131² = 39992519025826322, which contains 22 as substring.

Together with 141408133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 141408097 and 141408106.

It is not a weakly prime, because it can be changed into another prime (141408133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70704065 + 70704066.

It is an arithmetic number, because the mean of its divisors is an integer number (70704066).

Almost surely, 2^141408131 is an apocalyptic number.

141408131 is a deficient number, since it is larger than the sum of its proper divisors (1).

141408131 is an equidigital number, since it uses as much as digits as its factorization.

141408131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

The square root of 141408131 is about 11891.5150842943. The cubic root of 141408131 is about 520.9844897221.

The spelling of 141408131 in words is "one hundred forty-one million, four hundred eight thousand, one hundred thirty-one".