Base | Representation |
---|---|
bin | 10100100100111111100… |
… | …101100011101001000111 |
3 | 12000012001211102102102212 |
4 | 110210333211203221013 |
5 | 141132044412102221 |
6 | 3001344511254035 |
7 | 204110663413301 |
oct | 24447745435107 |
9 | 5005054372385 |
10 | 1414111050311 |
11 | 4a57a2905243 |
12 | 1aa092b1a31b |
13 | a347222819b |
14 | 4c62c74c971 |
15 | 26bb6dcbb5b |
hex | 1493f963a47 |
1414111050311 has 2 divisors, whose sum is σ = 1414111050312. Its totient is φ = 1414111050310.
The previous prime is 1414111050307. The next prime is 1414111050383. The reversal of 1414111050311 is 1130501114141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1414111050311 - 22 = 1414111050307 is a prime.
It is a super-3 number, since 3×14141110503113 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1414111050301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707055525155 + 707055525156.
It is an arithmetic number, because the mean of its divisors is an integer number (707055525156).
Almost surely, 21414111050311 is an apocalyptic number.
1414111050311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414111050311 is an equidigital number, since it uses as much as digits as its factorization.
1414111050311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 23.
Adding to 1414111050311 its reverse (1130501114141), we get a palindrome (2544612164452).
The spelling of 1414111050311 in words is "one trillion, four hundred fourteen billion, one hundred eleven million, fifty thousand, three hundred eleven".
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