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1414124211173 is a prime number
BaseRepresentation
bin10100100101000000010…
…111110000101111100101
312000012002202012001202012
4110211000113300233211
5141132111244224143
63001350101324005
7204111213316202
oct24450027605745
95005082161665
101414124211173
114a57aa284193
121aa097406605
13a3474b8568b
144c6303b6ca9
1526bb812b418
hex149405f0be5

1414124211173 has 2 divisors, whose sum is σ = 1414124211174. Its totient is φ = 1414124211172.

The previous prime is 1414124211169. The next prime is 1414124211221. The reversal of 1414124211173 is 3711124214141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 973099385764 + 441024825409 = 986458^2 + 664097^2 .

It is an emirp because it is prime and its reverse (3711124214141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1414124211173 - 22 = 1414124211169 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1414124211133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707062105586 + 707062105587.

It is an arithmetic number, because the mean of its divisors is an integer number (707062105587).

Almost surely, 21414124211173 is an apocalyptic number.

It is an amenable number.

1414124211173 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414124211173 is an equidigital number, since it uses as much as digits as its factorization.

1414124211173 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5376, while the sum is 32.

The spelling of 1414124211173 in words is "one trillion, four hundred fourteen billion, one hundred twenty-four million, two hundred eleven thousand, one hundred seventy-three".