14144223200111 has 2 divisors, whose sum is σ = 14144223200112. Its totient is φ = 14144223200110.

The previous prime is 14144223200039. The next prime is 14144223200113. The reversal of 14144223200111 is 11100232244141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14144223200111 - 2¹⁰ = 14144223199087 is a prime.

Together with 14144223200113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14144223200113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7072111600055 + 7072111600056.

It is an arithmetic number, because the mean of its divisors is an integer number (7072111600056).

Almost surely, 2^{14144223200111} is an apocalyptic number.

14144223200111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14144223200111 is an equidigital number, since it uses as much as digits as its factorization.

14144223200111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 14144223200111 its reverse (11100232244141), we get a palindrome (25244455444252).

The spelling of 14144223200111 in words is "fourteen trillion, one hundred forty-four billion, two hundred twenty-three million, two hundred thousand, one hundred eleven".