Base | Representation |
---|---|
bin | 10100100101010010101… |
… | …100000100101000100101 |
3 | 12000012220011110020122002 |
4 | 110211102230010220211 |
5 | 141133223432303123 |
6 | 3001440400215045 |
7 | 204121634411114 |
oct | 24452254045045 |
9 | 5005804406562 |
10 | 1414431525413 |
11 | 4a59477a39a5 |
12 | 1aa16230a485 |
13 | a34c374471a |
14 | 4c65d131c7b |
15 | 26bd50d2528 |
hex | 14952b04a25 |
1414431525413 has 2 divisors, whose sum is σ = 1414431525414. Its totient is φ = 1414431525412.
The previous prime is 1414431525349. The next prime is 1414431525461. The reversal of 1414431525413 is 3145251344141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 970386546724 + 444044978689 = 985082^2 + 666367^2 .
It is a cyclic number.
It is not a de Polignac number, because 1414431525413 - 26 = 1414431525349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1414431525713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707215762706 + 707215762707.
It is an arithmetic number, because the mean of its divisors is an integer number (707215762707).
Almost surely, 21414431525413 is an apocalyptic number.
It is an amenable number.
1414431525413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1414431525413 is an equidigital number, since it uses as much as digits as its factorization.
1414431525413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 115200, while the sum is 38.
Adding to 1414431525413 its reverse (3145251344141), we get a palindrome (4559682869554).
The spelling of 1414431525413 in words is "one trillion, four hundred fourteen billion, four hundred thirty-one million, five hundred twenty-five thousand, four hundred thirteen".
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