Base | Representation |
---|---|
bin | 11010010110001001… |
… | …01101111111001111 |
3 | 1100111202020111022221 |
4 | 31023010231333033 |
5 | 212431433230111 |
6 | 10255312120211 |
7 | 1010340446224 |
oct | 151304557717 |
9 | 40452214287 |
10 | 14144430031 |
11 | 5aa91866a6 |
12 | 28a8b36067 |
13 | 144550a734 |
14 | 98275194b |
15 | 57bb62371 |
hex | 34b12dfcf |
14144430031 has 2 divisors, whose sum is σ = 14144430032. Its totient is φ = 14144430030.
The previous prime is 14144430023. The next prime is 14144430073. The reversal of 14144430031 is 13003444141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14144430031 - 23 = 14144430023 is a prime.
It is a super-2 number, since 2×141444300312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14144429978 and 14144430005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14144430931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7072215015 + 7072215016.
It is an arithmetic number, because the mean of its divisors is an integer number (7072215016).
Almost surely, 214144430031 is an apocalyptic number.
14144430031 is a deficient number, since it is larger than the sum of its proper divisors (1).
14144430031 is an equidigital number, since it uses as much as digits as its factorization.
14144430031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14144430031 its reverse (13003444141), we get a palindrome (27147874172).
The spelling of 14144430031 in words is "fourteen billion, one hundred forty-four million, four hundred thirty thousand, thirty-one".
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