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14145105341 is a prime number
BaseRepresentation
bin11010010110001110…
…10010110110111101
31100111210111210200102
431023013102312331
5212432121332331
610255334410445
71010346261113
oct151307226675
940453453612
1014145105341
115aa95a8004
1228a9200a25
1314456b5c23
14982889ab3
1557bc474cb
hex34b1d2dbd

14145105341 has 2 divisors, whose sum is σ = 14145105342. Its totient is φ = 14145105340.

The previous prime is 14145105319. The next prime is 14145105343. The reversal of 14145105341 is 14350154141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7740304441 + 6404800900 = 87979^2 + 80030^2 .

It is a cyclic number.

It is not a de Polignac number, because 14145105341 - 214 = 14145088957 is a prime.

Together with 14145105343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14145105343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7072552670 + 7072552671.

It is an arithmetic number, because the mean of its divisors is an integer number (7072552671).

Almost surely, 214145105341 is an apocalyptic number.

It is an amenable number.

14145105341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14145105341 is an equidigital number, since it uses as much as digits as its factorization.

14145105341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 14145105341 its reverse (14350154141), we get a palindrome (28495259482).

The spelling of 14145105341 in words is "fourteen billion, one hundred forty-five million, one hundred five thousand, three hundred forty-one".