1414650111221 has 2 divisors, whose sum is σ = 1414650111222. Its totient is φ = 1414650111220.

The previous prime is 1414650111181. The next prime is 1414650111223. The reversal of 1414650111221 is 1221110564141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1104367690321 + 310282420900 = 1050889^2 + 557030^2 .

It is a cyclic number.

It is not a de Polignac number, because 1414650111221 - 2¹⁸ = 1414649849077 is a prime.

It is a super-2 number, since 2×1414650111221² (a number of 25 digits) contains 22 as substring.

Together with 1414650111223, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1414650111223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 707325055610 + 707325055611.

It is an arithmetic number, because the mean of its divisors is an integer number (707325055611).

Almost surely, 2^{1414650111221} is an apocalyptic number.

It is an amenable number.

1414650111221 is a deficient number, since it is larger than the sum of its proper divisors (1).

1414650111221 is an equidigital number, since it uses as much as digits as its factorization.

1414650111221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1920, while the sum is 29.

Adding to 1414650111221 its reverse (1221110564141), we get a palindrome (2635760675362).

The spelling of 1414650111221 in words is "one trillion, four hundred fourteen billion, six hundred fifty million, one hundred eleven thousand, two hundred twenty-one".