Base | Representation |
---|---|
bin | 1000001111001101000… |
… | …1010000010111110111 |
3 | 111112021210111011210112 |
4 | 2003303101100113313 |
5 | 4304313201343341 |
6 | 145002532013235 |
7 | 13140002021546 |
oct | 2036321202767 |
9 | 445253434715 |
10 | 141520340471 |
11 | 550225a7474 |
12 | 23516a6121b |
13 | 10464856643 |
14 | 6bc750815d |
15 | 3a34437aeb |
hex | 20f34505f7 |
141520340471 has 2 divisors, whose sum is σ = 141520340472. Its totient is φ = 141520340470.
The previous prime is 141520340399. The next prime is 141520340477. The reversal of 141520340471 is 174043025141.
141520340471 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141520340471 - 210 = 141520339447 is a prime.
It is a super-3 number, since 3×1415203404713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141520340477) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70760170235 + 70760170236.
It is an arithmetic number, because the mean of its divisors is an integer number (70760170236).
Almost surely, 2141520340471 is an apocalyptic number.
141520340471 is a deficient number, since it is larger than the sum of its proper divisors (1).
141520340471 is an equidigital number, since it uses as much as digits as its factorization.
141520340471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 32.
The spelling of 141520340471 in words is "one hundred forty-one billion, five hundred twenty million, three hundred forty thousand, four hundred seventy-one".
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