1418138411 has 2 divisors, whose sum is σ = 1418138412. Its totient is φ = 1418138410.

The previous prime is 1418138399. The next prime is 1418138413. The reversal of 1418138411 is 1148318141.

It is a strong prime.

It is an emirp because it is prime and its reverse (1148318141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1418138411 - 2¹⁰ = 1418137387 is a prime.

It is a super-2 number, since 2×1418138411² = 4022233105507209842, which contains 22 as substring.

Together with 1418138413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1418138413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 709069205 + 709069206.

It is an arithmetic number, because the mean of its divisors is an integer number (709069206).

Almost surely, 2^1418138411 is an apocalyptic number.

1418138411 is a deficient number, since it is larger than the sum of its proper divisors (1).

1418138411 is an equidigital number, since it uses as much as digits as its factorization.

1418138411 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3072, while the sum is 32.

The square root of 1418138411 is about 37658.1785406570. The cubic root of 1418138411 is about 1123.4994739889.

The spelling of 1418138411 in words is "one billion, four hundred eighteen million, one hundred thirty-eight thousand, four hundred eleven".