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14186655011 is a prime number
BaseRepresentation
bin11010011011001011…
…10010110100100011
31100121200200202010002
431031211302310203
5213023240430021
610303421130215
71011362402144
oct151545626443
940550622102
1014186655011
11601aaa6981
1228bb0b996b
1314511a2c29
149881c3acb
1558070350b
hex34d972d23

14186655011 has 2 divisors, whose sum is σ = 14186655012. Its totient is φ = 14186655010.

The previous prime is 14186654983. The next prime is 14186655013. The reversal of 14186655011 is 11055668141.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14186655011 is a prime.

It is a super-2 number, since 2×141866550112 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 14186655013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14186655013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7093327505 + 7093327506.

It is an arithmetic number, because the mean of its divisors is an integer number (7093327506).

Almost surely, 214186655011 is an apocalyptic number.

14186655011 is a deficient number, since it is larger than the sum of its proper divisors (1).

14186655011 is an equidigital number, since it uses as much as digits as its factorization.

14186655011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 38.

The spelling of 14186655011 in words is "fourteen billion, one hundred eighty-six million, six hundred fifty-five thousand, eleven".