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14200031411 is a prime number
BaseRepresentation
bin11010011100110001…
…10100100010110011
31100122121212100002022
431032120310202303
5213040202001121
610305015542055
71011614163326
oct151630644263
940577770068
1014200031411
116027602855
12290368a92b
131453ba7567
14989ca67bd
15581996aab
hex34e6348b3

14200031411 has 2 divisors, whose sum is σ = 14200031412. Its totient is φ = 14200031410.

The previous prime is 14200031359. The next prime is 14200031429. The reversal of 14200031411 is 11413000241.

It is a happy number.

14200031411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14200031411 - 226 = 14132922547 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14200031411.

It is not a weakly prime, because it can be changed into another prime (14200031431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7100015705 + 7100015706.

It is an arithmetic number, because the mean of its divisors is an integer number (7100015706).

Almost surely, 214200031411 is an apocalyptic number.

14200031411 is a deficient number, since it is larger than the sum of its proper divisors (1).

14200031411 is an equidigital number, since it uses as much as digits as its factorization.

14200031411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 14200031411 its reverse (11413000241), we get a palindrome (25613031652).

The spelling of 14200031411 in words is "fourteen billion, two hundred million, thirty-one thousand, four hundred eleven".