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14200424431 is a prime number
BaseRepresentation
bin11010011100110100…
…10100011111101111
31100122122121022012121
431032122110133233
5213040302040211
610305032213411
71011620421214
oct151632243757
940578538177
1014200424431
116027851066
12290383a267
131453cb440b
14989d69b0b
15581a23271
hex34e6947ef

14200424431 has 2 divisors, whose sum is σ = 14200424432. Its totient is φ = 14200424430.

The previous prime is 14200424363. The next prime is 14200424437. The reversal of 14200424431 is 13442400241.

It is a strong prime.

It is an emirp because it is prime and its reverse (13442400241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14200424431 - 221 = 14198327279 is a prime.

It is a super-2 number, since 2×142004244312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14200424396 and 14200424405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14200424437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7100212215 + 7100212216.

It is an arithmetic number, because the mean of its divisors is an integer number (7100212216).

Almost surely, 214200424431 is an apocalyptic number.

14200424431 is a deficient number, since it is larger than the sum of its proper divisors (1).

14200424431 is an equidigital number, since it uses as much as digits as its factorization.

14200424431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 14200424431 its reverse (13442400241), we get a palindrome (27642824672).

The spelling of 14200424431 in words is "fourteen billion, two hundred million, four hundred twenty-four thousand, four hundred thirty-one".