Base | Representation |
---|---|
bin | 10000111011011… |
… | …10110000111010 |
3 | 100220012221002100 |
4 | 20131232300322 |
5 | 242323331300 |
6 | 22031444230 |
7 | 3343035360 |
oct | 1035566072 |
9 | 326187070 |
10 | 142011450 |
11 | 73186339 |
12 | 3b686676 |
13 | 23562a59 |
14 | 14c09630 |
15 | c702700 |
hex | 876ec3a |
142011450 has 72 divisors (see below), whose sum is σ = 436052448. Its totient is φ = 32459040.
The previous prime is 142011449. The next prime is 142011451. The reversal of 142011450 is 54110241.
142011450 is a `hidden beast` number, since 14 + 201 + 1 + 450 = 666.
It is an interprime number because it is at equal distance from previous prime (142011449) and next prime (142011451).
It is a super-2 number, since 2×1420114502 = 40334503862205000, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (142011451) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 19392 + ... + 25691.
It is an arithmetic number, because the mean of its divisors is an integer number (6056284).
Almost surely, 2142011450 is an apocalyptic number.
142011450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
142011450 is an abundant number, since it is smaller than the sum of its proper divisors (294040998).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
142011450 is a wasteful number, since it uses less digits than its factorization.
142011450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45108 (or 45100 counting only the distinct ones).
The product of its (nonzero) digits is 160, while the sum is 18.
The square root of 142011450 is about 11916.8557094562. The cubic root of 142011450 is about 521.7243667471.
Adding to 142011450 its reverse (54110241), we get a palindrome (196121691).
It can be divided in two parts, 14201 and 1450, that added together give a palindrome (15651).
The spelling of 142011450 in words is "one hundred forty-two million, eleven thousand, four hundred fifty".
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