Base | Representation |
---|---|
bin | 100000010010100100000000… |
… | …101001100101001100101111 |
3 | 200121211022122102121010101121 |
4 | 200102210000221211030233 |
5 | 122103220314230330021 |
6 | 1222011530343521411 |
7 | 41625052055413336 |
oct | 4022440051451457 |
9 | 617738572533347 |
10 | 142013104542511 |
11 | 41282468270854 |
12 | 13b17111459267 |
13 | 6131a16bbaa27 |
14 | 270d68435ad1d |
15 | 1164147bbb741 |
hex | 812900a6532f |
142013104542511 has 2 divisors, whose sum is σ = 142013104542512. Its totient is φ = 142013104542510.
The previous prime is 142013104542481. The next prime is 142013104542583. The reversal of 142013104542511 is 115245401310241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 142013104542511 - 25 = 142013104542479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142013104543511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71006552271255 + 71006552271256.
It is an arithmetic number, because the mean of its divisors is an integer number (71006552271256).
Almost surely, 2142013104542511 is an apocalyptic number.
142013104542511 is a deficient number, since it is larger than the sum of its proper divisors (1).
142013104542511 is an equidigital number, since it uses as much as digits as its factorization.
142013104542511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 34.
Adding to 142013104542511 its reverse (115245401310241), we get a palindrome (257258505852752).
The spelling of 142013104542511 in words is "one hundred forty-two trillion, thirteen billion, one hundred four million, five hundred forty-two thousand, five hundred eleven".
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