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142014331141 is a prime number
BaseRepresentation
bin1000010001000010110…
…1101011100100000101
3111120120020000111121021
42010100231223210011
54311321132044031
6145123535551141
713155150616564
oct2042055534405
9446506014537
10142014331141
1155256429a21
122363438b4b1
1310512cb6407
146c32d77bdb
153a629b5511
hex2110b6b905

142014331141 has 2 divisors, whose sum is σ = 142014331142. Its totient is φ = 142014331140.

The previous prime is 142014331133. The next prime is 142014331157. The reversal of 142014331141 is 141133410241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 135137112100 + 6877219041 = 367610^2 + 82929^2 .

It is a cyclic number.

It is not a de Polignac number, because 142014331141 - 23 = 142014331133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142074331141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71007165570 + 71007165571.

It is an arithmetic number, because the mean of its divisors is an integer number (71007165571).

Almost surely, 2142014331141 is an apocalyptic number.

It is an amenable number.

142014331141 is a deficient number, since it is larger than the sum of its proper divisors (1).

142014331141 is an equidigital number, since it uses as much as digits as its factorization.

142014331141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 142014331141 its reverse (141133410241), we get a palindrome (283147741382).

The spelling of 142014331141 in words is "one hundred forty-two billion, fourteen million, three hundred thirty-one thousand, one hundred forty-one".