Base | Representation |
---|---|
bin | 100000010010101100110000… |
… | …101011110000000100110111 |
3 | 200121212012220020110201101011 |
4 | 200102230300223300010313 |
5 | 122103344040042233221 |
6 | 1222020122544413051 |
7 | 41625533645444665 |
oct | 4022546053600467 |
9 | 617765806421334 |
10 | 142022500352311 |
11 | 41286449a25817 |
12 | 13b18ab4017187 |
13 | 61328836732b7 |
14 | 270dcd6165c35 |
15 | 11644e79d01e1 |
hex | 812b30af0137 |
142022500352311 has 2 divisors, whose sum is σ = 142022500352312. Its totient is φ = 142022500352310.
The previous prime is 142022500352297. The next prime is 142022500352347. The reversal of 142022500352311 is 113253005220241.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (113253005220241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 142022500352311 - 221 = 142022498255159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142022500358311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71011250176155 + 71011250176156.
It is an arithmetic number, because the mean of its divisors is an integer number (71011250176156).
Almost surely, 2142022500352311 is an apocalyptic number.
142022500352311 is a deficient number, since it is larger than the sum of its proper divisors (1).
142022500352311 is an equidigital number, since it uses as much as digits as its factorization.
142022500352311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 142022500352311 its reverse (113253005220241), we get a palindrome (255275505572552).
The spelling of 142022500352311 in words is "one hundred forty-two trillion, twenty-two billion, five hundred million, three hundred fifty-two thousand, three hundred eleven".
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