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14202256811 is a prime number
BaseRepresentation
bin11010011101000010…
…10011110110101011
31100122210001101202112
431032201103312223
5213041234204221
610305135352535
71011642122351
oct151641236653
940583041675
1014202256811
116028892826
12290438274b
1314544a6472
1498a2c57d1
15581c8615b
hex34e853dab

14202256811 has 2 divisors, whose sum is σ = 14202256812. Its totient is φ = 14202256810.

The previous prime is 14202256793. The next prime is 14202256813. The reversal of 14202256811 is 11865220241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14202256811 is a prime.

Together with 14202256813, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14202256813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7101128405 + 7101128406.

It is an arithmetic number, because the mean of its divisors is an integer number (7101128406).

Almost surely, 214202256811 is an apocalyptic number.

14202256811 is a deficient number, since it is larger than the sum of its proper divisors (1).

14202256811 is an equidigital number, since it uses as much as digits as its factorization.

14202256811 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7680, while the sum is 32.

The spelling of 14202256811 in words is "fourteen billion, two hundred two million, two hundred fifty-six thousand, eight hundred eleven".