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14202522066611 is a prime number
BaseRepresentation
bin1100111010101100100001…
…0010000101111010110011
31212021202012011220220020102
43032223020102011322303
53330143231122112421
650112314253503015
72664045510460334
oct316531022057263
955252164826212
1014202522066611
11458628a4a185a
121714663aa1a6b
137c03a492a518
143715974a628b
151996909ab60b
hexceac8485eb3

14202522066611 has 2 divisors, whose sum is σ = 14202522066612. Its totient is φ = 14202522066610.

The previous prime is 14202522066527. The next prime is 14202522066613. The reversal of 14202522066611 is 11666022520241.

14202522066611 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14202522066611 is a prime.

Together with 14202522066613, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14202522066613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7101261033305 + 7101261033306.

It is an arithmetic number, because the mean of its divisors is an integer number (7101261033306).

Almost surely, 214202522066611 is an apocalyptic number.

14202522066611 is a deficient number, since it is larger than the sum of its proper divisors (1).

14202522066611 is an equidigital number, since it uses as much as digits as its factorization.

14202522066611 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 38.

Adding to 14202522066611 its reverse (11666022520241), we get a palindrome (25868544586852).

The spelling of 14202522066611 in words is "fourteen trillion, two hundred two billion, five hundred twenty-two million, sixty-six thousand, six hundred eleven".