1420301401031 has 2 divisors, whose sum is σ = 1420301401032. Its totient is φ = 1420301401030.

The previous prime is 1420301400989. The next prime is 1420301401033. The reversal of 1420301401031 is 1301041030241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1420301401031 is a prime.

It is a super-2 number, since 2×1420301401031² (a number of 25 digits) contains 22 as substring.

Together with 1420301401033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1420301400994 and 1420301401012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1420301401033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710150700515 + 710150700516.

It is an arithmetic number, because the mean of its divisors is an integer number (710150700516).

Almost surely, 2^{1420301401031} is an apocalyptic number.

1420301401031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1420301401031 is an equidigital number, since it uses as much as digits as its factorization.

1420301401031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1420301401031 its reverse (1301041030241), we get a palindrome (2721342431272).

The spelling of 1420301401031 in words is "one trillion, four hundred twenty billion, three hundred one million, four hundred one thousand, thirty-one".