Base | Representation |
---|---|
bin | 1100111010101110011100… |
… | …1101110100101011011001 |
3 | 1212021210112100110112102021 |
4 | 3032223213031310223121 |
5 | 3330200312001303423 |
6 | 50112441553134441 |
7 | 2664064411622461 |
oct | 316534715645331 |
9 | 55253470415367 |
10 | 14203041041113 |
11 | 4586526439001 |
12 | 171478985a421 |
13 | 7c04582c7022 |
14 | 37160639aba1 |
15 | 1996c132195d |
hex | ceae7374ad9 |
14203041041113 has 2 divisors, whose sum is σ = 14203041041114. Its totient is φ = 14203041041112.
The previous prime is 14203041041083. The next prime is 14203041041143. The reversal of 14203041041113 is 31114014030241.
It is a balanced prime because it is at equal distance from previous prime (14203041041083) and next prime (14203041041143).
It can be written as a sum of positive squares in only one way, i.e., 13105066088464 + 1097974952649 = 3620092^2 + 1047843^2 .
It is a cyclic number.
It is not a de Polignac number, because 14203041041113 - 25 = 14203041041081 is a prime.
It is not a weakly prime, because it can be changed into another prime (14203041041143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7101520520556 + 7101520520557.
It is an arithmetic number, because the mean of its divisors is an integer number (7101520520557).
Almost surely, 214203041041113 is an apocalyptic number.
It is an amenable number.
14203041041113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14203041041113 is an equidigital number, since it uses as much as digits as its factorization.
14203041041113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14203041041113 its reverse (31114014030241), we get a palindrome (45317055071354).
The spelling of 14203041041113 in words is "fourteen trillion, two hundred three billion, forty-one million, forty-one thousand, one hundred thirteen".
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