Base | Representation |
---|---|
bin | 11010011101001001… |
… | …00111101011001111 |
3 | 1100122211200110220121 |
4 | 31032210213223033 |
5 | 213041444440211 |
6 | 10305210125411 |
7 | 1011652365016 |
oct | 151644475317 |
9 | 40584613817 |
10 | 14203124431 |
11 | 6029325671 |
12 | 2904720867 |
13 | 145471b352 |
14 | 98a46da7d |
15 | 581da8271 |
hex | 34e927acf |
14203124431 has 2 divisors, whose sum is σ = 14203124432. Its totient is φ = 14203124430.
The previous prime is 14203124413. The next prime is 14203124483. The reversal of 14203124431 is 13442130241.
Together with previous prime (14203124413) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14203124431 - 219 = 14202600143 is a prime.
It is a super-2 number, since 2×142031244312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14203124396 and 14203124405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14203124401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7101562215 + 7101562216.
It is an arithmetic number, because the mean of its divisors is an integer number (7101562216).
Almost surely, 214203124431 is an apocalyptic number.
14203124431 is a deficient number, since it is larger than the sum of its proper divisors (1).
14203124431 is an equidigital number, since it uses as much as digits as its factorization.
14203124431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14203124431 its reverse (13442130241), we get a palindrome (27645254672).
The spelling of 14203124431 in words is "fourteen billion, two hundred three million, one hundred twenty-four thousand, four hundred thirty-one".
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