Base | Representation |
---|---|
bin | 1100111010110011100011… |
… | …1100000101100100001011 |
3 | 1212021221001220101201201211 |
4 | 3032230320330011210023 |
5 | 3330211114000422103 |
6 | 50113230012153551 |
7 | 2664143400625105 |
oct | 316547074054413 |
9 | 55257056351654 |
10 | 14204412123403 |
11 | 458706a376467 |
12 | 1714ab0a688b7 |
13 | 7c061638c318 |
14 | 3716d6502575 |
15 | 1997518a336d |
hex | ceb38f0590b |
14204412123403 has 2 divisors, whose sum is σ = 14204412123404. Its totient is φ = 14204412123402.
The previous prime is 14204412123401. The next prime is 14204412123409. The reversal of 14204412123403 is 30432121440241.
It is a happy number.
14204412123403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14204412123403 - 21 = 14204412123401 is a prime.
Together with 14204412123401, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (14204412123401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102206061701 + 7102206061702.
It is an arithmetic number, because the mean of its divisors is an integer number (7102206061702).
Almost surely, 214204412123403 is an apocalyptic number.
14204412123403 is a deficient number, since it is larger than the sum of its proper divisors (1).
14204412123403 is an equidigital number, since it uses as much as digits as its factorization.
14204412123403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 14204412123403 its reverse (30432121440241), we get a palindrome (44636533563644).
The spelling of 14204412123403 in words is "fourteen trillion, two hundred four billion, four hundred twelve million, one hundred twenty-three thousand, four hundred three".
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