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14204430423133 is a prime number
BaseRepresentation
bin1100111010110011101000…
…0001111001010001011101
31212021221010011211110020121
43032230322001321101131
53330211133142020013
650113231504314541
72664144012313066
oct316547201712135
955257104743217
1014204430423133
114587079735305
121714ab7012a51
137c061a0c8872
143716d8b0756d
151997532ba58d
hexceb3a07945d

14204430423133 has 2 divisors, whose sum is σ = 14204430423134. Its totient is φ = 14204430423132.

The previous prime is 14204430423041. The next prime is 14204430423173. The reversal of 14204430423133 is 33132403440241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7951740133689 + 6252690289444 = 2819883^2 + 2500538^2 .

It is a cyclic number.

It is not a de Polignac number, because 14204430423133 - 233 = 14195840488541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14204430423173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102215211566 + 7102215211567.

It is an arithmetic number, because the mean of its divisors is an integer number (7102215211567).

Almost surely, 214204430423133 is an apocalyptic number.

It is an amenable number.

14204430423133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14204430423133 is an equidigital number, since it uses as much as digits as its factorization.

14204430423133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 82944, while the sum is 34.

Adding to 14204430423133 its reverse (33132403440241), we get a palindrome (47336833863374).

The spelling of 14204430423133 in words is "fourteen trillion, two hundred four billion, four hundred thirty million, four hundred twenty-three thousand, one hundred thirty-three".