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14205435551 is a prime number
BaseRepresentation
bin11010011101011010…
…11011111010011111
31100200000000220011122
431032231123322133
5213043042414201
610305331441155
71012011131666
oct151655337237
940600026148
1014205435551
11602a663a8a
1229054561bb
13145504a288
1498a8b1ddd
155821b2e1b
hex34eb5be9f

14205435551 has 2 divisors, whose sum is σ = 14205435552. Its totient is φ = 14205435550.

The previous prime is 14205435527. The next prime is 14205435553. The reversal of 14205435551 is 15553450241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14205435551 is a prime.

It is a super-2 number, since 2×142054355512 (a number of 21 digits) contains 22 as substring.

Together with 14205435553, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14205435553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7102717775 + 7102717776.

It is an arithmetic number, because the mean of its divisors is an integer number (7102717776).

Almost surely, 214205435551 is an apocalyptic number.

14205435551 is a deficient number, since it is larger than the sum of its proper divisors (1).

14205435551 is an equidigital number, since it uses as much as digits as its factorization.

14205435551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60000, while the sum is 35.

Adding to 14205435551 its reverse (15553450241), we get a palindrome (29758885792).

The spelling of 14205435551 in words is "fourteen billion, two hundred five million, four hundred thirty-five thousand, five hundred fifty-one".