Base | Representation |
---|---|
bin | 1100111010111111000111… |
… | …0011100110000010011111 |
3 | 1212022020002001112020101101 |
4 | 3032233301303212002133 |
5 | 3330233442000311304 |
6 | 50114501445253531 |
7 | 2664313301504164 |
oct | 316576163460237 |
9 | 55266061466341 |
10 | 14207513682079 |
11 | 45884110a23a3 |
12 | 17156177042a7 |
13 | 7c09bbb11943 |
14 | 37190c3c406b |
15 | 199883d088a4 |
hex | cebf1ce609f |
14207513682079 has 2 divisors, whose sum is σ = 14207513682080. Its totient is φ = 14207513682078.
The previous prime is 14207513682077. The next prime is 14207513682113. The reversal of 14207513682079 is 97028631570241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14207513682079 - 21 = 14207513682077 is a prime.
Together with 14207513682077, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14207513682077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7103756841039 + 7103756841040.
It is an arithmetic number, because the mean of its divisors is an integer number (7103756841040).
It is a 1-persistent number, because it is pandigital, but 2⋅14207513682079 = 28415027364158 is not.
Almost surely, 214207513682079 is an apocalyptic number.
14207513682079 is a deficient number, since it is larger than the sum of its proper divisors (1).
14207513682079 is an equidigital number, since it uses as much as digits as its factorization.
14207513682079 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5080320, while the sum is 55.
The spelling of 14207513682079 in words is "fourteen trillion, two hundred seven billion, five hundred thirteen million, six hundred eighty-two thousand, seventy-nine".
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